Question-11315

Question Number 11315 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 20/Mar/17

Commented by chux last updated on 20/Mar/17

please can you tell me the name of any app for plotting and editing graph.

$$\mathrm{please}\:\mathrm{can}\:\mathrm{you}\:\mathrm{tell}\:\mathrm{me}\:\mathrm{the}\:\mathrm{name}\:\mathrm{of} \\ $$$$\mathrm{any}\:\mathrm{app}\:\mathrm{for}\:\mathrm{plotting}\:\mathrm{and}\:\mathrm{editing} \\ $$$$\mathrm{graph}. \\ $$

Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 20/Mar/17

Commented by mrW1 last updated on 20/Mar/17

B(−1,−1) A(1,1) y=x^3 y′=3x^2 L=∫_(−1) ^1 (√(1+(y′)^2 ))dx L=∫_(−1) ^1 (√(1+9x^4 ))dx =(1/( (√3)))∫(√(1+((√3)x)^4 ))d((√3)x) =(1/( (√3)))∫(√(1+t^4 ))dt with t=(√3)x I=∫(√(1+t^4 ))dt working...

$${B}\left(−\mathrm{1},−\mathrm{1}\right) \\ $$$${A}\left(\mathrm{1},\mathrm{1}\right) \\ $$$${y}={x}^{\mathrm{3}} \\ $$$${y}'=\mathrm{3}{x}^{\mathrm{2}} \\ $$$${L}=\int_{−\mathrm{1}} ^{\mathrm{1}} \sqrt{\mathrm{1}+\left({y}'\right)^{\mathrm{2}} }{dx} \\ $$$${L}=\int_{−\mathrm{1}} ^{\mathrm{1}} \sqrt{\mathrm{1}+\mathrm{9}{x}^{\mathrm{4}} }{dx} \\ $$$$=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\int\sqrt{\mathrm{1}+\left(\sqrt{\mathrm{3}}{x}\right)^{\mathrm{4}} }{d}\left(\sqrt{\mathrm{3}}{x}\right) \\ $$$$=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\int\sqrt{\mathrm{1}+{t}^{\mathrm{4}} }{dt}\:\:\:{with}\:{t}=\sqrt{\mathrm{3}}{x} \\ $$$${I}=\int\sqrt{\mathrm{1}+{t}^{\mathrm{4}} }{dt} \\ $$$$ \\ $$$${working}… \\ $$

Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 20/Mar/17