Menu Close

Question-11540




Question Number 11540 by tawa last updated on 28/Mar/17
Answered by sandy_suhendra last updated on 28/Mar/17
(1)  S=3 cm=0.03 m  m=7 g=7.10^(−3)  kg  V_o =450 m/s  V_t =175 m/s    W=ΔKE  ΣF.S = (1/2)m(V_t ^2  − V_o ^2 )  −F×0.03=(1/2)×7.10^(−3) ×(175^2 −450^2 )  −0.03F=−601.5625  F = 20,052.083 N
$$\left(\mathrm{1}\right) \\ $$$$\mathrm{S}=\mathrm{3}\:\mathrm{cm}=\mathrm{0}.\mathrm{03}\:\mathrm{m} \\ $$$$\mathrm{m}=\mathrm{7}\:\mathrm{g}=\mathrm{7}.\mathrm{10}^{−\mathrm{3}} \:\mathrm{kg} \\ $$$$\mathrm{V}_{\mathrm{o}} =\mathrm{450}\:\mathrm{m}/\mathrm{s} \\ $$$$\mathrm{V}_{\mathrm{t}} =\mathrm{175}\:\mathrm{m}/\mathrm{s} \\ $$$$ \\ $$$$\mathrm{W}=\Delta\mathrm{KE} \\ $$$$\Sigma\mathrm{F}.\mathrm{S}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\mathrm{m}\left(\mathrm{V}_{\mathrm{t}} ^{\mathrm{2}} \:−\:\mathrm{V}_{\mathrm{o}} ^{\mathrm{2}} \right) \\ $$$$−\mathrm{F}×\mathrm{0}.\mathrm{03}=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{7}.\mathrm{10}^{−\mathrm{3}} ×\left(\mathrm{175}^{\mathrm{2}} −\mathrm{450}^{\mathrm{2}} \right) \\ $$$$−\mathrm{0}.\mathrm{03F}=−\mathrm{601}.\mathrm{5625} \\ $$$$\mathrm{F}\:=\:\mathrm{20},\mathrm{052}.\mathrm{083}\:\mathrm{N} \\ $$
Commented by tawa last updated on 28/Mar/17
God bless you sir.
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\: \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *