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Question-12074

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Question Number 12074 by sin (x) last updated on 11/Apr/17
Answered by ajfour last updated on 11/Apr/17
Commented by ajfour last updated on 11/Apr/17
M is the mid-point of CD. let side of triangle be a . BM=BC−CM =a−((a+8)/2)=((a−8)/2) BE=BM/cos 60 = a−8 AB= a AE = AB−BE =a−(a−8)=8cm.
Misthemid−pointofCD.letsideoftrianglebea.BM=BC−CM=a−a+82=a−82BE=BM/cos60=a−8AB=aAE=AB−BE=a−(a−8)=8cm.

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