Question Number 12096 by sin (x) last updated on 13/Apr/17
Answered by ajfour last updated on 13/Apr/17
Commented by ajfour last updated on 13/Apr/17
$${As}\:\:\:{CD}={AE} \\ $$$${EM}=\frac{\mathrm{1}}{\mathrm{2}}{CD}=\frac{\mathrm{1}}{\mathrm{2}}{AE} \\ $$$$\mathrm{sin}\:\alpha\:=\:\frac{{EM}}{{AE}}=\:\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\Rightarrow\:\:\boldsymbol{\alpha}\:=\:\mathrm{30}°\:\:. \\ $$