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Question-12365




Question Number 12365 by chux last updated on 20/Apr/17
Commented by mrW1 last updated on 21/Apr/17
Definition of Lambert W function:  if y=xe^x   then x=W(y)  i.e. y=W(y)e^(W(y))     All what you have to do is to transform  your equation into the form like this  Y=Xe^X   then you can use the W−function to get  X=W(Y)    Sometimes it′s usefull to know   a^b =e^(ln a^b ) =e^(bln a)     For example: solve log x^2 =(x/8)  ⇒x^2 =10^(((x/8)))   ⇒x=±10^(((x/(16))))   ⇒x=±e^(((x/(16)))ln 10)   ⇒x×e^(−((ln 10)/(16))x) =±1  ⇒(−((ln 10)/(16))x)×e^((−((ln 10)/(16))x)) =±((ln 10)/(16))  ⇒−((ln 10)/(16))x=W(±((ln 10)/(16)))  ⇒x=−((W(±((ln 10)/(16))))/((ln 10)/(16)))  ≈−((W(±0.143911))/(0.143911))  = { ((−((W(0.143911))/(0.143911))=−((0.126776)/(0.143911))=−0.88093)),((−((W(−0.143911))/(0.143911))= { ((−((−0.170697)/(0.143911))=1.18613)),((−((−3.05550)/(0.143911))=21.23178)) :})) :}    For example: solve x^x =16  ⇒xln x=ln 16  ⇒(ln x)e^((ln x)) =ln 16  ⇒ln x=W(ln 16)  ⇒x=e^(W(ln 16)) =((ln 16)/(W(ln 16)))  ≈((2.771588)/(W(2.771588)))=((2.771588)/(1.00973))=2.74587    In internet you may find calculators  to evaluate W function values.
DefinitionofLambertWfunction:ify=xexthenx=W(y)i.e.y=W(y)eW(y)AllwhatyouhavetodoistotransformyourequationintotheformlikethisY=XeXthenyoucanusetheWfunctiontogetX=W(Y)Sometimesitsusefulltoknowab=elnab=eblnaForexample:solvelogx2=x8x2=10(x8)x=±10(x16)x=±e(x16)ln10x×eln1016x=±1(ln1016x)×e(ln1016x)=±ln1016ln1016x=W(±ln1016)x=W(±ln1016)ln1016W(±0.143911)0.143911={W(0.143911)0.143911=0.1267760.143911=0.88093W(0.143911)0.143911={0.1706970.143911=1.186133.055500.143911=21.23178Forexample:solvexx=16xlnx=ln16(lnx)e(lnx)=ln16lnx=W(ln16)x=eW(ln16)=ln16W(ln16)2.771588W(2.771588)=2.7715881.00973=2.74587IninternetyoumayfindcalculatorstoevaluateWfunctionvalues.
Commented by chux last updated on 20/Apr/17
i ve always had problems with the  final simplification using   LAMBART W FUNCTION .  is it that there s a special calculator  for it or what.     please help me out if theres any    calculator or rule for it.Also help   with its properties or rules.    Thanks for always helping.
ivealwayshadproblemswiththefinalsimplificationusingLAMBARTWFUNCTION.isitthattheresaspecialcalculatorforitorwhat.pleasehelpmeoutiftheresanycalculatororruleforit.Alsohelpwithitspropertiesorrules.Thanksforalwayshelping.
Commented by chux last updated on 21/Apr/17
can you recomend any calculator   for it.
canyourecomendanycalculatorforit.
Commented by mrW1 last updated on 21/Apr/17
There was a very nice online   calculator at www.had2know.com,  but the site is no longer valid.  I use geogebra to evaluate W(a)  indirectly.
Therewasaveryniceonlinecalculatoratwww.had2know.com,butthesiteisnolongervalid.IusegeogebratoevaluateW(a)indirectly.
Commented by chux last updated on 21/Apr/17
thank you very much sir
thankyouverymuchsir

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