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Question-12649




Question Number 12649 by tawa last updated on 28/Apr/17
Answered by mrW1 last updated on 28/Apr/17
((300+500+700−440−1000)/2)=30  ⇒30 persons involved lost of injury  to all the three.
$$\frac{\mathrm{300}+\mathrm{500}+\mathrm{700}−\mathrm{440}−\mathrm{1000}}{\mathrm{2}}=\mathrm{30} \\ $$$$\Rightarrow\mathrm{30}\:{persons}\:{involved}\:{lost}\:{of}\:{injury} \\ $$$${to}\:{all}\:{the}\:{three}. \\ $$
Commented by tawa last updated on 28/Apr/17
God bless you sir.
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$
Commented by mrW1 last updated on 29/Apr/17
Explanation:  x persons with injury to only one of the three  y persons with injury to two of the three  z persons with injury to all of the three  x+y+z=1000       ...(i)  x+2y+3z=300+500+700     ...(ii)  y=440  ⇒z=((300+500+700−1000−440)/2)=30  ⇒x=1000−440−30=530
$${Explanation}: \\ $$$${x}\:{persons}\:{with}\:{injury}\:{to}\:{only}\:{one}\:{of}\:{the}\:{three} \\ $$$${y}\:{persons}\:{with}\:{injury}\:{to}\:{two}\:{of}\:{the}\:{three} \\ $$$${z}\:{persons}\:{with}\:{injury}\:{to}\:{all}\:{of}\:{the}\:{three} \\ $$$${x}+{y}+{z}=\mathrm{1000}\:\:\:\:\:\:\:…\left({i}\right) \\ $$$${x}+\mathrm{2}{y}+\mathrm{3}{z}=\mathrm{300}+\mathrm{500}+\mathrm{700}\:\:\:\:\:…\left({ii}\right) \\ $$$${y}=\mathrm{440} \\ $$$$\Rightarrow{z}=\frac{\mathrm{300}+\mathrm{500}+\mathrm{700}−\mathrm{1000}−\mathrm{440}}{\mathrm{2}}=\mathrm{30} \\ $$$$\Rightarrow{x}=\mathrm{1000}−\mathrm{440}−\mathrm{30}=\mathrm{530} \\ $$
Commented by tawa last updated on 28/Apr/17
God bless you sir.
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$
Commented by tawa last updated on 28/Apr/17
sir is it z = ((......)/3)  ???   or   ((.......)/2) ???  because you said 3z
$$\mathrm{sir}\:\mathrm{is}\:\mathrm{it}\:\mathrm{z}\:=\:\frac{……}{\mathrm{3}}\:\:???\:\:\:\mathrm{or}\:\:\:\frac{…….}{\mathrm{2}}\:??? \\ $$$$\mathrm{because}\:\mathrm{you}\:\mathrm{said}\:\mathrm{3z} \\ $$
Commented by mrW1 last updated on 28/Apr/17
(ii)−(i) gets  y+2z=300+500+700−1000  2z=300+500+700−1000−440  z=((300+500+700−1000−440)/2)
$$\left({ii}\right)−\left({i}\right)\:{gets} \\ $$$${y}+\mathrm{2}{z}=\mathrm{300}+\mathrm{500}+\mathrm{700}−\mathrm{1000} \\ $$$$\mathrm{2}{z}=\mathrm{300}+\mathrm{500}+\mathrm{700}−\mathrm{1000}−\mathrm{440} \\ $$$${z}=\frac{\mathrm{300}+\mathrm{500}+\mathrm{700}−\mathrm{1000}−\mathrm{440}}{\mathrm{2}} \\ $$
Commented by tawa last updated on 28/Apr/17
i understand now sir. God bless you sir.
$$\mathrm{i}\:\mathrm{understand}\:\mathrm{now}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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