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Question-12773




Question Number 12773 by tawa last updated on 01/May/17
Answered by mrW1 last updated on 01/May/17
Q7  ⇒Answer C
$${Q}\mathrm{7} \\ $$$$\Rightarrow{Answer}\:{C} \\ $$
Commented by mrW1 last updated on 01/May/17
Commented by mrW1 last updated on 01/May/17
f(2)−f(0)=∫_0 ^2 f′(x)dx=A_1 ≈(2/3)×2×3=4  f(4)−f(2)=∫_2 ^4 f′(x)dx=A_2 ≈−(2/3)×2×1=−(4/3)
$${f}\left(\mathrm{2}\right)−{f}\left(\mathrm{0}\right)=\int_{\mathrm{0}} ^{\mathrm{2}} {f}'\left({x}\right){dx}=\boldsymbol{{A}}_{\mathrm{1}} \approx\frac{\mathrm{2}}{\mathrm{3}}×\mathrm{2}×\mathrm{3}=\mathrm{4} \\ $$$${f}\left(\mathrm{4}\right)−{f}\left(\mathrm{2}\right)=\int_{\mathrm{2}} ^{\mathrm{4}} {f}'\left({x}\right){dx}=\boldsymbol{{A}}_{\mathrm{2}} \approx−\frac{\mathrm{2}}{\mathrm{3}}×\mathrm{2}×\mathrm{1}=−\frac{\mathrm{4}}{\mathrm{3}} \\ $$
Commented by tawa last updated on 01/May/17
God bless you sir.
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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