Question Number 12829 by tawa last updated on 03/May/17
Answered by mrW1 last updated on 03/May/17
$$\left(\mathrm{1}\right) \\ $$$${let}'{s}\:{say}\:{the}\:{mean}\:{mark}\:{of}\:{the}\:\mathrm{6}\:{students} \\ $$$${who}\:{passed}\:{is}\:{x}. \\ $$$${the}\:{total}\:{mark}\:{of}\:{the}\:\mathrm{2}\:{students}\:{who} \\ $$$${failed}\:{is}\:{y}. \\ $$$${y}\leqslant\mathrm{2}×\mathrm{44}=\mathrm{88} \\ $$$$\mathrm{8}×\mathrm{53}=\mathrm{6}{x}+{y}\leqslant\mathrm{6}{x}+\mathrm{2}×\mathrm{44} \\ $$$${x}\geqslant\frac{\mathrm{8}×\mathrm{53}−\mathrm{2}×\mathrm{44}}{\mathrm{6}}=\mathrm{56} \\ $$
Commented by tawa last updated on 03/May/17
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$
Answered by mrW1 last updated on 03/May/17
$$\left(\mathrm{2}\right) \\ $$$$\mathrm{48}<\frac{\mathrm{45}+{x}}{\mathrm{2}}<\mathrm{52} \\ $$$$\mathrm{2}×\mathrm{48}−\mathrm{45}<{x}<\mathrm{2}×\mathrm{52}−\mathrm{45} \\ $$$$\mathrm{51}<{x}<\mathrm{57} \\ $$$$\mathrm{52}\leqslant{x}\leqslant\mathrm{56} \\ $$
Commented by tawa last updated on 03/May/17
$$\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$