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Question-12874




Question Number 12874 by tawa last updated on 04/May/17
Answered by mrW1 last updated on 05/May/17
(dy/dx)=6x−5  y=∫(6x−5)dx=3x^2 −5x+C  5=3×2^2 −5×2+C  ⇒C=3  ⇒the curve is y=3x^2 −5x+3
$$\frac{{dy}}{{dx}}=\mathrm{6}{x}−\mathrm{5} \\ $$$${y}=\int\left(\mathrm{6}{x}−\mathrm{5}\right){dx}=\mathrm{3}{x}^{\mathrm{2}} −\mathrm{5}{x}+{C} \\ $$$$\mathrm{5}=\mathrm{3}×\mathrm{2}^{\mathrm{2}} −\mathrm{5}×\mathrm{2}+{C} \\ $$$$\Rightarrow{C}=\mathrm{3} \\ $$$$\Rightarrow{the}\:{curve}\:{is}\:{y}=\mathrm{3}{x}^{\mathrm{2}} −\mathrm{5}{x}+\mathrm{3} \\ $$
Commented by tawa last updated on 05/May/17
God bless you sir.
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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