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Question-12909




Question Number 12909 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 06/May/17
Answered by nume1114 last updated on 07/May/17
    a^2 (a+1)+b^2 (b+1)+5ab  =a^3 +b^3 +a^2 +b^2 +5ab  =(a+b)^3 −3ab(a+b)+(a+b)^2 +3ab  =1−3ab+1+3ab  =2
a2(a+1)+b2(b+1)+5ab=a3+b3+a2+b2+5ab=(a+b)33ab(a+b)+(a+b)2+3ab=13ab+1+3ab=2

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