Question-131994

Question Number 131994 by liberty last updated on 10/Feb/21

Commented by liberty last updated on 10/Feb/21

old unswered

Answered by EDWIN88 last updated on 10/Feb/21

(1) n (S) = \frac{15!}{5! . 5! . 5!}; n (A) = 3! \times \frac{12!}{4! . 4! . 4!}

P (A) = \frac{6 \times 12! \times 5! \times 5! \times 5!}{4! \times 4! \times 4! \times 15!} = \frac{25}{91}

Commented by liberty last updated on 10/Feb/21

Vielen Dank Sir Edwin

Answered by EDWIN88 last updated on 10/Feb/21

(2) n (A) = 3 \times C_{2}^{12} \times C_{5}^{10} \times C_{5}^{5} = \frac{3 \times 12!}{2! 5! . 5!}

P (A) = \frac{3 \times 12! \times 5! \times 5! \times 5!}{2 \times 5! \times 5! \times 15!} = \frac{3 \times 12! \times 120}{2 \times 15 \times 14 \times 13 \times 12!}

= \frac{3 \times 60}{15 \times 14 \times 13} = \frac{12}{14 \times 13} = \frac{6}{91}

Facebook Tweet Pin