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Question-132064




Question Number 132064 by I want to learn more last updated on 10/Feb/21
Commented by mr W last updated on 11/Feb/21
(m_1 +m_2 )a=(m_1 −m_2 )g  a=((m_1 −m_2 )/(m_1 +m_2 ))g  v=(√(2ah))=(√((2gh(m_1 −m_2 ))/(m_1 +m_2 )))
$$\left({m}_{\mathrm{1}} +{m}_{\mathrm{2}} \right){a}=\left({m}_{\mathrm{1}} −{m}_{\mathrm{2}} \right){g} \\ $$$${a}=\frac{{m}_{\mathrm{1}} −{m}_{\mathrm{2}} }{{m}_{\mathrm{1}} +{m}_{\mathrm{2}} }{g} \\ $$$${v}=\sqrt{\mathrm{2}{ah}}=\sqrt{\frac{\mathrm{2}{gh}\left({m}_{\mathrm{1}} −{m}_{\mathrm{2}} \right)}{{m}_{\mathrm{1}} +{m}_{\mathrm{2}} }} \\ $$
Commented by I want to learn more last updated on 11/Feb/21
Thanks sir,  i really areciate.
$$\mathrm{Thanks}\:\mathrm{sir},\:\:\mathrm{i}\:\mathrm{really}\:\mathrm{areciate}. \\ $$

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