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Question-132220




Question Number 132220 by aurpeyz last updated on 12/Feb/21
Answered by Olaf last updated on 12/Feb/21
P^→  = 6(cos60°i^→ +sin60°j^→ )  P^→  = 6((1/2)i^→ +((√3)/2)j^→ )  P^→  = 3i^→ +3(√3)j^→
$$\overset{\rightarrow} {\mathrm{P}}\:=\:\mathrm{6}\left(\mathrm{cos60}°\overset{\rightarrow} {{i}}+\mathrm{sin60}°\overset{\rightarrow} {{j}}\right) \\ $$$$\overset{\rightarrow} {\mathrm{P}}\:=\:\mathrm{6}\left(\frac{\mathrm{1}}{\mathrm{2}}\overset{\rightarrow} {{i}}+\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}\overset{\rightarrow} {{j}}\right) \\ $$$$\overset{\rightarrow} {\mathrm{P}}\:=\:\mathrm{3}\overset{\rightarrow} {{i}}+\mathrm{3}\sqrt{\mathrm{3}}\overset{\rightarrow} {{j}} \\ $$
Commented by aurpeyz last updated on 12/Feb/21
the answer is not there??  you rotated the angle from the   posotive x−axis?
$${the}\:{answer}\:{is}\:{not}\:{there}?? \\ $$$${you}\:{rotated}\:{the}\:{angle}\:{from}\:{the}\: \\ $$$${posotive}\:{x}−{axis}? \\ $$

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