Question Number 132373 by Ari last updated on 13/Feb/21
Answered by Ari last updated on 13/Feb/21
Answered by mr W last updated on 14/Feb/21
Commented by mr W last updated on 14/Feb/21
$${AB}=\sqrt{\mathrm{6}^{\mathrm{2}} +\mathrm{8}^{\mathrm{2}} }=\mathrm{10} \\ $$$$\left(\mathrm{6}−{x}\right)+\left(\mathrm{8}−{x}\right)=\mathrm{10} \\ $$$$\Rightarrow{x}=\mathrm{2} \\ $$$${shaded}\:{area}=\frac{\mathrm{1}}{\mathrm{2}}×\left(\mathrm{8}−\mathrm{2}\right)×\mathrm{2}=\mathrm{6} \\ $$