Question Number 134396 by I want to learn more last updated on 03/Mar/21
![](https://www.tinkutara.com/question/19199.png)
Commented by mr W last updated on 03/Mar/21
![P+Q=2×10×sin ((75°)/2)=12.2 unit](https://www.tinkutara.com/question/Q134397.png)
$${P}+{Q}=\mathrm{2}×\mathrm{10}×\mathrm{sin}\:\frac{\mathrm{75}°}{\mathrm{2}}=\mathrm{12}.\mathrm{2}\:{unit} \\ $$
Commented by mr W last updated on 03/Mar/21
![](https://www.tinkutara.com/question/19202.png)
Commented by I want to learn more last updated on 03/Mar/21
![Thanks sir. I understand now. God bless you sir.](https://www.tinkutara.com/question/Q134409.png)
$$\mathrm{Thanks}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{understand}\:\mathrm{now}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$
Answered by liberty last updated on 03/Mar/21
![∣P+Q∣=(√(200−200 cos 75°)) = 10(√(2−2cos 75°)) ≈ 12.175](https://www.tinkutara.com/question/Q134415.png)
$$\mid\mathrm{P}+\mathrm{Q}\mid=\sqrt{\mathrm{200}−\mathrm{200}\:\mathrm{cos}\:\mathrm{75}°} \\ $$$$\:=\:\mathrm{10}\sqrt{\mathrm{2}−\mathrm{2cos}\:\mathrm{75}°}\: \\ $$$$\:\approx\:\mathrm{12}.\mathrm{175} \\ $$
Commented by I want to learn more last updated on 03/Mar/21
![Thanks sir. i appreciate.](https://www.tinkutara.com/question/Q134423.png)
$$\mathrm{Thanks}\:\mathrm{sir}.\:\mathrm{i}\:\mathrm{appreciate}. \\ $$