Question-135213

Question Number 135213 by mr W last updated on 11/Mar/21

Commented by mr W last updated on 11/Mar/21

i f t h e t r u c k c a n s t a r t w i t h a n

a c c e l e r a t i o n a, f i n d t h e f r i c t i o n

c o e f f i c i e n t b e t w e e n t i r e s a n d g r o u n d .

Commented by mr W last updated on 12/Mar/21

M_{2} = \frac{L_{1} M}{L_{1} + L_{2}}

M_{1} = \frac{L_{2} M}{L_{1} + L_{2}}

μ (M_{2} - M_{1}) g = M a

\Rightarrow μ = \frac{L_{1} + L_{2}}{L_{1} - L_{2}} \times \frac{a}{g}

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