Question Number 135658 by I want to learn more last updated on 14/Mar/21
Answered by mr W last updated on 15/Mar/21
Commented by mr W last updated on 15/Mar/21
$${shaded}\:{area}={big}\:{circle}\:−\:{small}\:{circle} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\pi{R}^{\mathrm{2}} −\pi{r}^{\mathrm{2}} =\pi\left({R}^{\mathrm{2}} −{r}^{\mathrm{2}} \right) \\ $$$${r}^{\mathrm{2}} +\left(\frac{\mathrm{16}}{\mathrm{2}}\right)^{\mathrm{2}} ={R}^{\mathrm{2}} \\ $$$$\Rightarrow{R}^{\mathrm{2}} −{r}^{\mathrm{2}} =\left(\frac{\mathrm{16}}{\mathrm{2}}\right)^{\mathrm{2}} = \\ $$$$\Rightarrow{shaded}\:{area}=\pi\left(\frac{\mathrm{16}}{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{64}\pi\:{units} \\ $$
Commented by I want to learn more last updated on 15/Mar/21
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir},\:\mathrm{i}\:\mathrm{appreciate}. \\ $$