Question-135976

Question Number 135976 by I want to learn more last updated on 17/Mar/21

Answered by mr W last updated on 17/Mar/21

\frac{x}{\sin 90 °} = \frac{2}{\sin ∠ A D C} \dots (i)

\frac{\sin 30 °}{3} = \frac{\sin ∠ B D C}{y} \dots (i i)

\sin ∠ B D C = \sin (180 ° - ∠ A D C) = \sin ∠ A D C

(i) \times (i i) :

\frac{x}{\sin 90 °} \times \frac{\sin 30 °}{3} = \frac{2}{y}

\Rightarrow x y = \frac{2 \times 3 \times \sin 90 °}{\sin 30 °} = \frac{6}{\frac{1}{2}} = 12

Commented by I want to learn more last updated on 17/Mar/21

Thanks sir . I appreciate .

Commented by I want to learn more last updated on 17/Mar/21

Sir please tag your question on projectile that an object strike the

wall and bounced back .

Commented by mr W last updated on 17/Mar/21

Q 135558

Commented by otchereabdullai@gmail.com last updated on 17/Mar/21

fantastic!

Commented by I want to learn more last updated on 18/Mar/21

Thanks sir . I appreciate