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Question-136283




Question Number 136283 by JulioCesar last updated on 20/Mar/21
Answered by Ar Brandon last updated on 20/Mar/21
∫e^(g(x)) [f(x)g′(x)+f ′(x)]dx=e^(g(x)) f(x)
$$\int\mathrm{e}^{\mathrm{g}\left(\mathrm{x}\right)} \left[\mathrm{f}\left(\mathrm{x}\right)\mathrm{g}'\left(\mathrm{x}\right)+\mathrm{f}\:'\left(\mathrm{x}\right)\right]\mathrm{dx}=\mathrm{e}^{\mathrm{g}\left(\mathrm{x}\right)} \mathrm{f}\left(\mathrm{x}\right) \\ $$

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