Question-136761

Question Number 136761 by I want to learn more last updated on 25/Mar/21

Commented by I want to learn more last updated on 25/Mar/21

$$\mathrm{I}\:\mathrm{appreciate}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}. \\ $$

Answered by mr W last updated on 25/Mar/21

ΔBDA∼ΔBAC ((BD)/(AB))=((AB)/(BC)) ⇒BD×BC=AB^2 =6^2 area BCE=((CE×BC)/2)=((BD×BC)/2) =(6^2 /2)=18

$$\Delta{BDA}\sim\Delta{BAC} \\ $$$$\frac{{BD}}{{AB}}=\frac{{AB}}{{BC}} \\ $$$$\Rightarrow{BD}×{BC}={AB}^{\mathrm{2}} =\mathrm{6}^{\mathrm{2}} \\ $$$${area}\:{BCE}=\frac{{CE}×{BC}}{\mathrm{2}}=\frac{{BD}×{BC}}{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{6}^{\mathrm{2}} }{\mathrm{2}}=\mathrm{18} \\ $$

Commented by I want to learn more last updated on 25/Mar/21

$$\mathrm{What}\:\mathrm{is}\:\mathrm{this}\:\mathrm{sign}\:\mathrm{sir}\:\:\left(\sim\right) \\ $$

Commented by mr W last updated on 25/Mar/21

$${not}\:{yet}\:{learnt}\:{geometry}\:{about} \\ $$$${similar}\:{triangles}?\:{then}\:{you}\:{can}\:{not} \\ $$$${understand}\:{the}\:{working}. \\ $$

Commented by I want to learn more last updated on 25/Mar/21

I don′t know the symbol represent similar triangle sir. Thanks. I understand better now sir

$$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{know}\:\mathrm{the}\:\mathrm{symbol}\:\mathrm{represent}\:\mathrm{similar}\:\mathrm{triangle}\:\mathrm{sir}. \\ $$$$\mathrm{Thanks}.\:\mathrm{I}\:\mathrm{understand}\:\mathrm{better}\:\mathrm{now}\:\mathrm{sir} \\ $$

Commented by mr W last updated on 25/Mar/21