Question-137209

Question Number 137209 by JulioCesar last updated on 31/Mar/21

Answered by bemath last updated on 31/Mar/21

\int {(\sec^{2} x - 1)}^{2} \sec x dx

= \int (\sec^{5} x - 2 \sec^{3} x + \sec x) dx

now it easy to solve

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