Question-137700

Question Number 137700 by peter frank last updated on 05/Apr/21

Commented by mr W last updated on 05/Apr/21

{i t}^{'} s n o t t r u e!

e x a m p l e :

b = c = - 1, a = \frac{1}{\sqrt[3]{2}}

\frac{1}{a^{3}} + \frac{1}{b^{3}} + \frac{1}{c^{3}} = 0

b u t {(a + b + c)}^{3} = {(\frac{1}{\sqrt[3]{2}} - 2)}^{3} \neq 27 a b c = \frac{27}{\sqrt[3]{2}}

Commented by peter frank last updated on 05/Apr/21

t h a n k y o u s o m u c h f o r c o n f i r m a t i o n