Question Number 138120 by Ari last updated on 10/Apr/21
Commented by Ari last updated on 10/Apr/21
$$\mathrm{If}\:\mathrm{anyone}\:\mathrm{could}\:\mathrm{help}? \\ $$
Answered by nimnim last updated on 10/Apr/21
$$\left.{Answer}\::\:{A}\right)\mathrm{7} \\ $$$$\Box\mathrm{214}\rightarrow\left(\mathrm{2}+\mathrm{1}+\mathrm{4}\right)=\mathrm{7} \\ $$$$ \mathrm{48}\rightarrow\left(\mathrm{4}×\mathrm{8}\right)=\mathrm{32} \\ $$$$\bigtriangleup\mathrm{27}\rightarrow\left(\mathrm{7}−\mathrm{2}\right)=\mathrm{5} \\ $$$$\therefore\bigtriangleup \Box\mathrm{6754239}=\bigtriangleup \left(\mathrm{6}+\mathrm{7}+\mathrm{5}+\mathrm{4}+\mathrm{2}+\mathrm{3}+\mathrm{9}\right) \\ $$$$=\bigtriangleup \mathrm{36}=\bigtriangleup\left(\mathrm{3}×\mathrm{6}\right) \\ $$$$=\bigtriangleup\mathrm{18}=\left(\mathrm{8}−\mathrm{1}\right)=\mathrm{7}\checkmark \\ $$
Commented by Ari last updated on 10/Apr/21
Ok,Thanks a lot!
Answered by Ñï= last updated on 10/Apr/21
$$\bigtriangleup\circledcirc\Box\mathrm{6754239} \\ $$$$=\bigtriangleup\circledcirc\left(\mathrm{6}+\mathrm{7}+\mathrm{5}+\mathrm{4}+\mathrm{2}+\mathrm{3}+\mathrm{9}\right) \\ $$$$=\bigtriangleup\circledcirc\mathrm{36} \\ $$$$=\bigtriangleup\left(\mathrm{3}×\mathrm{6}\right) \\ $$$$=\bigtriangleup\mathrm{18} \\ $$$$=\mathrm{8}−\mathrm{1} \\ $$$$=\mathrm{7} \\ $$$${possible}\:{ans}\:{is}\:\mathrm{7}. \\ $$