Question Number 138338 by mohammad17 last updated on 12/Apr/21
Commented by mohammad17 last updated on 12/Apr/21
$${help}\:{me}\:{sirlease} \\ $$
Answered by mr W last updated on 12/Apr/21
$${Q}\mathrm{1}: \\ $$$${p}=\frac{\mathrm{1}+\mathrm{3}}{\mathrm{2}^{\mathrm{3}} }=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$${Q}\mathrm{2}: \\ $$$${p}=\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{3}} }=\frac{\mathrm{7}}{\mathrm{8}} \\ $$$${Q}\mathrm{3}: \\ $$$${p}=\frac{\mathrm{3}}{\mathrm{2}^{\mathrm{3}} }=\frac{\mathrm{3}}{\mathrm{8}} \\ $$