Question Number 138456 by I want to learn more last updated on 13/Apr/21
Commented by mr W last updated on 13/Apr/21
$${sum}\:{of}\:{shaded}\:{areas}\:{is}\:{the}\:{red}\:{triangle} \\ $$$${which}\:{is}\:\mathrm{1}/\mathrm{4}\:{of}\:{the}\:{square}. \\ $$
Commented by peter frank last updated on 13/Apr/21
$${sorry}\:{sir}\:{why}\:{are}\:{u}\:{divided} \\ $$$${by}\:{four}? \\ $$
Commented by I want to learn more last updated on 13/Apr/21
$$\mathrm{Find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{shaded}\:\mathrm{part}. \\ $$
Commented by mr W last updated on 14/Apr/21
$${easy}\:{to}\:{see}: \\ $$$${shaded}\:{area}=\frac{{square}}{\mathrm{4}}=\frac{\mathrm{6}×\mathrm{6}}{\mathrm{4}}=\mathrm{9} \\ $$
Commented by mr W last updated on 13/Apr/21
Commented by I want to learn more last updated on 13/Apr/21
$$\mathrm{Wow},\:\mathrm{thanks}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{appreciate}. \\ $$
Answered by cherokeesay last updated on 14/Apr/21
$$\mathrm{6} \\ $$