Question Number 138579 by Jamshidbek last updated on 15/Apr/21
Answered by MJS_new last updated on 16/Apr/21
$${x}\approx\mathrm{5}.\mathrm{40343170} \\ $$
Commented by MJS_new last updated on 16/Apr/21
$$\mathrm{we}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate} \\ $$$${x}^{{x}^{{x}} } =\mathrm{2017}^{\mathrm{2017}} \\ $$$${x}^{{x}} \mathrm{ln}\:{x}\:−\mathrm{2017ln}\:\mathrm{2017}\:=\mathrm{0} \\ $$$$\mathrm{now}\:\mathrm{use}\:\mathrm{a}\:\mathrm{calculator} \\ $$
Commented by Jamshidbek last updated on 16/Apr/21
$$\mathrm{I}\:\mathrm{need}\:\mathrm{solution} \\ $$