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Question-139075




Question Number 139075 by bramlexs22 last updated on 22/Apr/21
Answered by mr W last updated on 22/Apr/21
tan α=(x/(144))  tan β=(x/(144+81))=(x/(225))  tan γ=(x/(225+99))=(x/(324))  tan γ=tan (90°−α−β)=(1/(tan (α+β)))  (x/(324))=((1−(x/(144))×(x/(225)))/((x/(144))+(x/(225))))=((3600)/(41x))(1−(x^2 /(32400)))  77x^2 =36×32400  ⇒x=((1080)/( (√(77))))≈123.077
tanα=x144tanβ=x144+81=x225tanγ=x225+99=x324tanγ=tan(90°αβ)=1tan(α+β)x324=1x144×x225x144+x225=360041x(1x232400)77x2=36×32400x=108077123.077

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