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Question-139140




Question Number 139140 by mathlove last updated on 23/Apr/21
Answered by TheSupreme last updated on 23/Apr/21
sin(x)=x−(x^3 /3)+o(x^3 )  lim_x ((2019x−2019x+((2019^3 )/3)x^3 )/(2020x−2020x+((2020^3 )/3)x^3 ))=(((2019)/(2020)))^3
$${sin}\left({x}\right)={x}−\frac{{x}^{\mathrm{3}} }{\mathrm{3}}+{o}\left({x}^{\mathrm{3}} \right) \\ $$$${li}\underset{{x}} {{m}}\frac{\mathrm{2019}{x}−\mathrm{2019}{x}+\frac{\mathrm{2019}^{\mathrm{3}} }{\mathrm{3}}{x}^{\mathrm{3}} }{\mathrm{2020}{x}−\mathrm{2020}{x}+\frac{\mathrm{2020}^{\mathrm{3}} }{\mathrm{3}}{x}^{\mathrm{3}} }=\left(\frac{\mathrm{2019}}{\mathrm{2020}}\right)^{\mathrm{3}} \\ $$

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