Question Number 139545 by aliibrahim1 last updated on 28/Apr/21
Answered by mr W last updated on 28/Apr/21
Commented by mr W last updated on 28/Apr/21
$$\frac{\mathrm{sin}\:\alpha}{\mathrm{sin}\:\mathrm{48}}=\frac{\mathrm{sin}\:\left(\mathrm{54}−\alpha\right)}{\mathrm{sin}\:\mathrm{66}}=\frac{\mathrm{sin}\:\mathrm{54}\:\mathrm{cos}\:\alpha−\mathrm{cos}\:\mathrm{54}\:\mathrm{sin}\:\alpha}{\mathrm{sin}\:\mathrm{66}} \\ $$$$\mathrm{tan}\:\alpha=\frac{\mathrm{sin}\:\mathrm{54}}{\frac{\mathrm{sin}\:\mathrm{66}}{\mathrm{sin}\:\mathrm{48}}+\mathrm{cos}\:\mathrm{54}}\Rightarrow\alpha=\mathrm{24}° \\ $$
Commented by aliibrahim1 last updated on 28/Apr/21
$${thx}\:{good}\:{sir} \\ $$