Menu Close

Question-139998




Question Number 139998 by bramlexs22 last updated on 03/May/21
Commented by bramlexs22 last updated on 03/May/21
find the area of ΔABC
$$\mathrm{find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\Delta\mathrm{ABC} \\ $$
Answered by som(math1967) last updated on 03/May/21
△ADE∼△AEC  ∴(y/6)=((24)/y)⇒y=(√(6×24))=12  Area △ABC=(1/2)×BC×y  =(1/2)×48×12=288squnit
$$\bigtriangleup{ADE}\sim\bigtriangleup{AEC} \\ $$$$\therefore\frac{{y}}{\mathrm{6}}=\frac{\mathrm{24}}{{y}}\Rightarrow{y}=\sqrt{\mathrm{6}×\mathrm{24}}=\mathrm{12} \\ $$$${Area}\:\bigtriangleup{ABC}=\frac{\mathrm{1}}{\mathrm{2}}×{BC}×{y} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{48}×\mathrm{12}=\mathrm{288}{squnit} \\ $$
Commented by bramlexs22 last updated on 03/May/21
in diagram , where ΔADS?
$$\mathrm{in}\:\mathrm{diagram}\:,\:\mathrm{where}\:\Delta\mathrm{ADS}? \\ $$
Commented by som(math1967) last updated on 03/May/21
Sorry I wrote S insted E
$${Sorry}\:{I}\:{wrote}\:{S}\:{insted}\:{E} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *