Question Number 140042 by denzel last updated on 03/May/21
Answered by MJS_new last updated on 03/May/21
$$\mathrm{254}=\frac{\mathrm{1269}}{\mathrm{4}+\mathrm{46e}^{−.\mathrm{3}{t}} } \\ $$$$\mathrm{just}\:\mathrm{transform}\:\mathrm{it} \\ $$$$\mathrm{e}^{−.\mathrm{3}{t}} =\frac{\frac{\mathrm{1269}}{\mathrm{254}}−\mathrm{4}}{\mathrm{46}}=\frac{\mathrm{11}}{\mathrm{508}} \\ $$$$−.\mathrm{3}{t}=\mathrm{ln}\:\frac{\mathrm{11}}{\mathrm{508}} \\ $$$${t}=\frac{\mathrm{ln}\:\frac{\mathrm{11}}{\mathrm{508}}}{−.\mathrm{3}}\approx\mathrm{12}.\mathrm{78}\:\Rightarrow\:\mathrm{given}\:\mathrm{answer}\:\mathrm{is}\:\mathrm{wrong} \\ $$