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Question-140276




Question Number 140276 by cherokeesay last updated on 06/May/21
Answered by mr W last updated on 06/May/21
Commented by mr W last updated on 06/May/21
α=60°−45°=15°=(π/(12))  (A/2)=((10^2 )/2)×(π/(12))−((5×((√(10^2 −5^2 ))−5))/2)  ⇒A=((25π)/3)−25((√3)−1)
$$\alpha=\mathrm{60}°−\mathrm{45}°=\mathrm{15}°=\frac{\pi}{\mathrm{12}} \\ $$$$\frac{{A}}{\mathrm{2}}=\frac{\mathrm{10}^{\mathrm{2}} }{\mathrm{2}}×\frac{\pi}{\mathrm{12}}−\frac{\mathrm{5}×\left(\sqrt{\mathrm{10}^{\mathrm{2}} −\mathrm{5}^{\mathrm{2}} }−\mathrm{5}\right)}{\mathrm{2}} \\ $$$$\Rightarrow{A}=\frac{\mathrm{25}\pi}{\mathrm{3}}−\mathrm{25}\left(\sqrt{\mathrm{3}}−\mathrm{1}\right) \\ $$
Commented by cherokeesay last updated on 06/May/21
very nice !  thank you sir !
$${very}\:{nice}\:! \\ $$$${thank}\:{you}\:{sir}\:! \\ $$

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