Question-140702

Question Number 140702 by help last updated on 11/May/21

Answered by liberty last updated on 12/May/21

(3) \frac{y^{2}}{2} = - x y \frac{dy}{dx}

\Rightarrow - \frac{dx}{x} = \frac{2 dy}{y}

\Rightarrow - \ln x + c = 2 \ln y

\Rightarrow - \ln Cx = \ln y^{2}

\Rightarrow \frac{1}{Cx} = y^{2}

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