Question-141323

Question Number 141323 by mathocean1 last updated on 17/May/21

Answered by mr W last updated on 17/May/21

Commented by mr W last updated on 17/May/21

\cos α = \frac{R - r}{R + r}

B C = \frac{2 R}{\tan \frac{α}{2}} = 2 R \sqrt{\frac{1 + \cos α}{1 - \cos α}} = 2 R \sqrt{\frac{R}{r}}

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