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Question-141568




Question Number 141568 by sarkor last updated on 20/May/21
Commented by Dwaipayan Shikari last updated on 20/May/21
Area between this curves  (√x)=x^2 ⇒x=1 (Meeting point)  ∫_0 ^1 (√x)−x^2 dx=(2/3)−(1/3)=(1/3)
$${Area}\:{between}\:{this}\:{curves} \\ $$$$\sqrt{{x}}={x}^{\mathrm{2}} \Rightarrow{x}=\mathrm{1}\:\left({Meeting}\:{point}\right) \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} \sqrt{{x}}−{x}^{\mathrm{2}} {dx}=\frac{\mathrm{2}}{\mathrm{3}}−\frac{\mathrm{1}}{\mathrm{3}}=\frac{\mathrm{1}}{\mathrm{3}} \\ $$
Commented by Dwaipayan Shikari last updated on 20/May/21

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