Question Number 141651 by mathsuji last updated on 21/May/21
Commented by MJS_new last updated on 22/May/21
$$\mathrm{it}'\mathrm{s}\:\mathrm{wrong}. \\ $$$${a}={b}={c}=\mathrm{0}\:\Rightarrow\:\mathrm{6}\sqrt{\mathrm{2}}>\mathrm{0} \\ $$$${a}={b}={c}=−\sqrt{\mathrm{3}}\:\Rightarrow\:\mathrm{6}\sqrt{\mathrm{2}}>−\mathrm{6}\sqrt{\mathrm{3}}>−\mathrm{9}\sqrt{\mathrm{3}} \\ $$
Commented by mathsuji last updated on 22/May/21
$${sorry}\:{sir},\:{a},{b},{c}>\mathrm{0} \\ $$