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Question-142341




Question Number 142341 by mohammad17 last updated on 30/May/21
Commented by mohammad17 last updated on 30/May/21
how can solve this
$${how}\:{can}\:{solve}\:{this} \\ $$
Answered by Dwaipayan Shikari last updated on 30/May/21
A.A=A^2 cos0°=∣A∣^2       (  A and A are parallel because they are same)
$${A}.{A}={A}^{\mathrm{2}} {cos}\mathrm{0}°=\mid{A}\mid^{\mathrm{2}} \:\: \\ $$$$\:\:\left(\:\:{A}\:{and}\:{A}\:{are}\:{parallel}\:{because}\:{they}\:{are}\:{same}\right) \\ $$

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