Question-142401

Question Number 142401 by mohammad17 last updated on 31/May/21

Commented by mohammad17 last updated on 31/May/21

h e l p m e s i r p l e a s e

Answered by mr W last updated on 31/May/21

Q 1

p r e s s u r e a t r : p (r)

r = 250 m m = 0.25 m

r_{0} = r - t = 250 - 120 = 130 m m = 0.13 m

d p = ρ r ω^{2} d r

\int_{0}^{p} d p = \int_{r_{0}}^{r} ρ r ω^{2} d r

\Rightarrow p = \frac{ρ ω^{2} (r^{2} - r_{0}^{2})}{2}

= \frac{1}{2} \times 2200 \times 160^{2} \times (0 . 25^{2} - 0 . 13^{2})

= 1284096 P a \approx 1.284 M P a

Facebook Tweet Pin