Question Number 142822 by aupo14 last updated on 05/Jun/21
Answered by MJS_new last updated on 06/Jun/21
$${x}^{\mathrm{2}} ={i}+{x}\:\Rightarrow\:{x}=\frac{\mathrm{1}+\sqrt{\mathrm{1}+\mathrm{4i}}}{\mathrm{2}}=\frac{\mathrm{2}+\sqrt{\mathrm{2}\left(\mathrm{1}+\sqrt{\mathrm{17}}\right)}}{\mathrm{4}}+\frac{\sqrt{\mathrm{2}\left(−\mathrm{1}+\sqrt{\mathrm{17}}\right)}}{\mathrm{4}}\mathrm{i} \\ $$$$\mathrm{the}\:\mathrm{other}\:\mathrm{solution}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{fit}\:\left(\mathrm{just}\:\mathrm{give}\:\mathrm{it}\:\mathrm{a}\:\mathrm{try}\right) \\ $$