Question-143072

Question Number 143072 by Feruzbek last updated on 09/Jun/21

Answered by mr W last updated on 09/Jun/21

s a y x = n + f

10000 n = {(n + f)}^{2} ⩾ n^{2}

n^{2} - 10000 n ⩽ 0

\Rightarrow 0 ⩽ n ⩽ 10000 \dots (i)

10000 n = {(n + f)}^{2} < {(n + 1)}^{2}

n^{2} - 9998 n + 1 > 0

\Rightarrow n < 1 o r n > 9997 \dots (i i)

\Rightarrow n = 0 o r 9998 o r 9999 o r 10000

\Rightarrow x = 100 \sqrt{n}

i . e . x = 0 o r

= 100 \sqrt{9998} o r

= 100 \sqrt{9999} = 300 \sqrt{1111} o r

= 10000

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