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Question-143168

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Question Number 143168 by Cwesi last updated on 10/Jun/21
Commented by mr W last updated on 10/Jun/21
x=42+40+32=114°
x=42+40+32=114°
Commented by mr W last updated on 10/Jun/21
Answered by Cwesi last updated on 11/Jun/21
∠BOC=42+40+32 ∠BOC=82+32 ∠BOC=114°
∠BOC=42+40+32∠BOC=82+32∠BOC=114°
Answered by JDamian last updated on 10/Jun/21
A^� +B^� +C^� =180° 40°+(32°+b)+(42°+c)=180° b+c=180°−114° x+b+c=180° x=180°−(b+c) x=180°−(b+c)=180°−(180°−114°) x=114°
A^+B^+C^=180°40°+(32°+b)+(42°+c)=180°b+c=180°−114°x+b+c=180°x=180°−(b+c)x=180°−(b+c)=180°−(180°−114°)x=114°
Commented by Frederick last updated on 11/Jun/21
correc answer
correcanswer

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