Question-143586

Question Number 143586 by mim24 last updated on 16/Jun/21

Commented by muallim_riyoziyot last updated on 16/Jun/21

x a a

Answered by bobhans last updated on 16/Jun/21

\tan θ = ∣ \frac{- \frac{2}{3} - (- \frac{3}{2})}{1 + (- \frac{2}{3}) (- \frac{3}{2})} ∣

= ∣ \frac{\frac{3}{2} - \frac{2}{3}}{1 + 1} ∣= \frac{5}{12}

\Rightarrow θ = \arctan (\frac{5}{12}) = 0.394791

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