Question Number 4318 by Rasheed Soomro last updated on 10/Jan/16
Commented by 123456 last updated on 10/Jan/16
$${x}/\mathrm{2} \\ $$
Commented by prakash jain last updated on 10/Jan/16
$$\angle\mathrm{DCB}={x}/\mathrm{2} \\ $$
Answered by prakash jain last updated on 10/Jan/16
$$\mathrm{Angle}\:\mathrm{DBC}\:\mathrm{cannot}\:\mathrm{be}\:\mathrm{found}\:\mathrm{with}\:\mathrm{given} \\ $$$$\mathrm{information}. \\ $$
Commented by Rasheed Soomro last updated on 11/Jan/16
$${Mistake}\:{in}\:{diagram}.{Sorry}! \\ $$