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Question-4739




Question Number 4739 by shashi kashyap last updated on 04/Mar/16
Answered by 123456 last updated on 04/Mar/16
x^2 −xy^2 +3y^2 +2=0  (3−x)y^2 =−x^2 −2  y^2 =((x^2 +2)/(x−3))  y=(√((x^2 +2)/(x−3)))
$${x}^{\mathrm{2}} −{xy}^{\mathrm{2}} +\mathrm{3}{y}^{\mathrm{2}} +\mathrm{2}=\mathrm{0} \\ $$$$\left(\mathrm{3}−{x}\right){y}^{\mathrm{2}} =−{x}^{\mathrm{2}} −\mathrm{2} \\ $$$${y}^{\mathrm{2}} =\frac{{x}^{\mathrm{2}} +\mathrm{2}}{{x}−\mathrm{3}} \\ $$$${y}=\sqrt{\frac{{x}^{\mathrm{2}} +\mathrm{2}}{{x}−\mathrm{3}}} \\ $$
Commented by prakash jain last updated on 04/Mar/16
y=(√((x^2 +2)/(x−3)))
$${y}=\sqrt{\frac{{x}^{\mathrm{2}} +\mathrm{2}}{{x}−\mathrm{3}}} \\ $$
Commented by 123456 last updated on 04/Mar/16
thanks
$$\mathrm{thanks} \\ $$

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