Question Number 4739 by shashi kashyap last updated on 04/Mar/16
Answered by 123456 last updated on 04/Mar/16
$${x}^{\mathrm{2}} −{xy}^{\mathrm{2}} +\mathrm{3}{y}^{\mathrm{2}} +\mathrm{2}=\mathrm{0} \\ $$$$\left(\mathrm{3}−{x}\right){y}^{\mathrm{2}} =−{x}^{\mathrm{2}} −\mathrm{2} \\ $$$${y}^{\mathrm{2}} =\frac{{x}^{\mathrm{2}} +\mathrm{2}}{{x}−\mathrm{3}} \\ $$$${y}=\sqrt{\frac{{x}^{\mathrm{2}} +\mathrm{2}}{{x}−\mathrm{3}}} \\ $$
Commented by prakash jain last updated on 04/Mar/16
$${y}=\sqrt{\frac{{x}^{\mathrm{2}} +\mathrm{2}}{{x}−\mathrm{3}}} \\ $$
Commented by 123456 last updated on 04/Mar/16
$$\mathrm{thanks} \\ $$