Question-5189

Question Number 5189 by sanusihammed last updated on 28/Apr/16

Commented by FilupSmith last updated on 28/Apr/16

Q 1

V = I R

I = \frac{V}{R} \Rightarrow I = \frac{12}{16 + 8}

I = \frac{1}{2}

Voltage over 16 ohm :

V = I R

V = \frac{1}{2} \cdot 16

V_{1} = 8 v

Voltage over 8 ohm :

V = I R

V = \frac{1}{2} \cdot 8

V_{2} = 4

Chect voltages :

V = V_{1} + V_{2}

12 = 8 + 4

12 = 12

∴ Correct