Question-6476 Tinku Tara June 3, 2023 Algebra 0 Comments FacebookTweetPin Question Number 6476 by sanusihammed last updated on 28/Jun/16 Answered by Rasheed Soomro last updated on 28/Jun/16 Givenequation:x2−px+8=0Sumoftheroots=−coefficientofxcoefficientofx2=−−p1=pAndthisisequaltoa+(a+2)=2a+2Hencep=2a+2Productoftheroots=constantcoefficientofx2=81=8Andthisisequaltoa(a+2)Hencea(a+2)=8a2+2a−8=0(a+4)(a−2)=0a=−4∣a=2Ifa=−4⇒p=2(−4)+2=−6[∵p=2a+2]Ifa=2⇒p=2(2)+2=6Hencep=±6 Commented by sanusihammed last updated on 28/Jun/16 Thankssomuch Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Find-a-solution-of-the-form-x-x-r-k-0-c-k-x-k-x-gt-0-for-xy-y-y-0-Next Next post: find-f-0-arctan-x-x-2-3-2-dx-with-real- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.
![Given equation: x^2 −px+8=0 Sum of the roots =−((coefficient of x)/(coefficient of x^2 )) =−((−p)/1)=p And this is equal to a+(a+2)=2a+2 Hence p=2a+2 Product of the roots=((constant)/(coefficient of x^2 )) =(8/1)=8 And this is equal to a(a+2) Hence a(a+2)=8 a^2 +2a−8=0 (a+4)(a−2)=0 a=−4 ∣ a=2 If a=−4⇒p=2(−4)+2=−6 [∵ p=2a+2] If a=2⇒p=2(2)+2=6 Hence p=±6](https://www.tinkutara.com/question/Q6477.png)
