Question-66518 Tinku Tara June 3, 2023 Limits 0 Comments FacebookTweetPin Question Number 66518 by Masumsiddiqui399@gmail.com last updated on 16/Aug/19 Commented by mathmax by abdo last updated on 16/Aug/19 letf(x)=xx−aax−acha7gementx−a=tgivelimx→af(x)=limt→0(t+a)t+a−aat=limt→0(t+a)3−a3t((t+a)t+a+aa)=limt→0t3+3t2a+3ta2t{(t+a)t+a+aa)=limt→0t2+3at+3a2(t+a)t+a+aa=3a22aa=32a Commented by Tony Lin last updated on 16/Aug/19 limx→axx−aax−a=limx→ax32−a32x−a=limx→a32x121=32a Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: prove-that-x-1-2-x-2-2-s-2-2p-x-1-and-x-2-are-roots-of-ax-2-bx-c-0-Next Next post: jika-fungsi-f-x-px-2-p-1-x-6-mencapai-nilai-tertingi-untuk-x-1-maka-nilai-p- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.