Question Number 66846 by John Kaloki Musau last updated on 20/Aug/19
Commented by John Kaloki Musau last updated on 20/Aug/19
The diagram above shows a cross-section of a bottle. The lower part ABC is a hemisphere of radius 5.2cm and the upper part is a frustrum of a cone. The top radius of the frustrum is one third of the radius of the hemisphere. The hemispherical part is conpletely filled with water as shown in the diagram.
When the container is inverted, the water now conpletely fills only the frustfum part.
(a) Determine the height of the frustrum part.
(b) Find the surface area of the frustrum part of the bottle.
Commented by John Kaloki Musau last updated on 20/Aug/19
$$\boldsymbol{{The}}\:\boldsymbol{{answers}}\:\boldsymbol{{are}}: \\ $$$$\left(\boldsymbol{{a}}\right)\mathrm{7}.\mathrm{2}\boldsymbol{{cm}} \\ $$$$\left(\boldsymbol{{b}}\right)\:\mathrm{183}.\mathrm{6}\boldsymbol{{cm}}^{\mathrm{2}} \\ $$$$\boldsymbol{{please}}\:\boldsymbol{{show}}\:\boldsymbol{{me}}\:\boldsymbol{{how}}\:\boldsymbol{{to}}\:\boldsymbol{{calculate}} \\ $$$$\boldsymbol{{them}} \\ $$