Question Number 66986 by Mr Jor last updated on 21/Aug/19
Commented by Mr Jor last updated on 21/Aug/19
$${The}\:{metal}\:{solid}\:{above}\:{is}\:{made}\:{up} \\ $$$${by}\:{joining}\:{a}\:{hemisphere}\:{of}\:{radius} \\ $$$$\mathrm{7}{cm}\:{to}\:{a}\:{cylinder}\:{of}\:{the}\:{same}\:{radius}. \\ $$$${The}\:{mass}\:{and}\:{density}\:{of}\:{the}\:{solid} \\ $$$${are}\:\mathrm{40}{kg}\:{and}\:\mathrm{17}.\mathrm{5}{gm}\:{per}\:{cm}^{\mathrm{3}} , \\ $$$${respectively}.{Calculate}\:{the}\:{height} \\ $$$${of}\:{the}\:{cylindrical}\:{part}\:{of}\:{the}\:{solid}. \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{Ans}:\mathrm{10}.\mathrm{18}{cm} \\ $$