Question Number 67025 by Masumsiddiqui399@gmail.com last updated on 21/Aug/19
Commented by Rasheed.Sindhi last updated on 22/Aug/19
$${x}^{{x}^{{x}+\mathrm{5}} } =\:^{\mathrm{3}} \sqrt{\mathrm{3}} \\ $$$$\left({x}^{{x}^{{x}+\mathrm{5}} } \right)^{\mathrm{3}} =\left(\:^{\mathrm{3}} \sqrt{\mathrm{3}}\right)^{\mathrm{3}} \\ $$$${x}^{\mathrm{3}{x}^{{x}+\mathrm{5}} } =\mathrm{3} \\ $$$${x}^{\mathrm{3}{x}^{{x}+\mathrm{5}} } .\mathrm{3}^{{x}+\mathrm{5}} =\mathrm{3}.\mathrm{3}^{{x}+\mathrm{5}} \\ $$$${x}^{\mathrm{3}{x}^{{x}+\mathrm{5}} +{x}+\mathrm{5}} =\mathrm{3}^{{x}+\mathrm{6}} \\ $$$$…. \\ $$
Commented by mr W last updated on 22/Aug/19
$${Rasheed}\:{sir}: \\ $$$${please}\:{have}\:{a}\:{look}\:{at}\:{Q}\mathrm{66832}.\:{any} \\ $$$${idea}\:{for}\:{an}\:{easier}\:{way}\:{to}\:{solve}? \\ $$$${thanks}\:{sir}! \\ $$
Commented by Rasheed.Sindhi last updated on 22/Aug/19
$${Sir}\:{I}\:{think}\:{that}\:'{chinese}\:{remainder}\:{theorm}' \\ $$$${is}\:{most}\:{proper}\:{way}.{However}\:{you}\:{have}\:{done} \\ $$$${it}\:{in}\:{a}\:{creative}\:{way}! \\ $$